MHT CET202313 May 2023Evening ShiftMathematicsCircleActual
The abscissae of two points A and B are the roots of the equation x^2+2 a x-b^2=0 and their ordinates are roots of the equation y^2+2 p y- q ^2=0 . Then the equation of the circle with AB as diameter is given by
Options
- Ax^2+y^2-2 a x-2 p y+ ( b ^2+ q ^2 )=0
- Bx^2+y^2-2 a x-2 p y- ( b ^2+ q ^2 )=0
- Cx^2+y^2+2 a x+2 p y+ ( b ^2+ q ^2 )=0
- Dx^2+y^2+2 a x+2 p y- ( b ^2+ q ^2 )=0
Correct answer
D. x^2+y^2+2 a x+2 p y- ( b ^2+ q ^2 )=0
Step-by-step solution
Let A (x₁, y₁ ) and B (x₂, y₂ ) . According to the given condition, x₁+x₂=-2 a , x₁ x₂=- b ^2y₁+y₂=-2 p , y₁ y₂=- q ^2 The equation of the circle with A (x₁, y₁ ) and B (x₂, y₂ ) as the end points of diameter is (x-x₁ ) (x-x₂ )+ (y-y₁ ) (y-y₂ )=0 x^2+y^2-x (x₁+x₂ )-y (y₁+y₂ )+x₁ x₂+y₁ y₂=0 x^2+y^2+2 a x+2 p y- b ^2- q ^2=0