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AP EAMCET202421 May 2024Evening ShiftMathematicsApplication of DerivativesActual

The equation of the tangent to the curve y=x^3-2 x+7 at the point (1,6) is

Options

  1. Ay=x+5
  2. B2 x+y=8
  3. Cx+y=7
  4. Dx+2 y=13

Correct answer

A. y=x+5

Step-by-step solution

y=x^3-2 x+7 d y d x =3 x^2- .2 d y d x |_ x=1 =1 Equation of tangent is y-6 x-1 =1 x-y+5=0 y=x+5

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