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MHT CET202311 May 2023Morning ShiftMathematicsCircleActual

Number of common tangents to the circles x^2+y^2-6 x-14 y+48=0 and x^2+y^2-6 x=0 are

Options

  1. A0
  2. B1
  3. C4
  4. D2

Correct answer

C. 4

Step-by-step solution

array ll & x^2+y^2-6 x-14 y+48=0 & C ₁(3,7), r ₁= 10 & Again x^2+y^2-6 x=0 & C ₂(3,0), r ₂=3 array Now l ( C ₁ C ₂ )= distance between centres aligned & l ( C ₁ C ₂ )= 0^2+7^2 =7 and & & r ₁+ r ₂= 10 +3 < l ( C ₁ C ₂ ) aligned The given circles are disjoint. Number of common tangents is 4 .

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