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MHT CET202210 Aug 2022Morning ShiftMathematicsCircleActual

The equation of a circle, which passes through the centre of the circle x^2+y^2+8 x+10 y-7=0 and is concentric with the circle. 2 x^2+2 y^2-8 x-12 y-9=0 , is

Options

  1. Ax^2+y^2-4 x+6 y-87=0
  2. Bx^2+y^2+4 x+6 y-87=0
  3. Cx^2+y^2+4 x+6 y+87=0
  4. Dx^2+y^2-4 x-6 y-87=0

Correct answer

D. x^2+y^2-4 x-6 y-87=0

Step-by-step solution

The required circle is concentric with the circle 2 x^2+2 y^2-8 x-12 y-9=0 i.e, centre is at (2,3) and passes through the centre of the circle x^2+y^2+8 x+10 y-7=0 i.e., through (-4,-5) Hence, the required equation is aligned & (x-2)^2+(y-3)^2=(2+4)^2+(3+5)^2 & x^2+y^2-4 x-6 y-87=0 aligned

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