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MHT CET20227 Aug 2022Morning ShiftMathematicsCircleActual

If the lines 2 x-3 y=5 and 3 x-4 y=7 are the diameters of a circle of area154sq units, then equation of the circle is ( . Take . = 22 7 )

Options

  1. Ax^2+y^2-2 x+2 y-47=0
  2. Bx^2+y^2-2 x+2 y-49=0
  3. Cx^2+y^2-2 x-2 y-47=0
  4. Dx^2+y^2-2 x-2 y-49=0

Correct answer

A. x^2+y^2-2 x+2 y-47=0

Step-by-step solution

Centre is point of intersection of 2 x-3 y=5 and 3 x-4 y=7i e (1,-1) and radius r is such that r^2=154 r=7 Hence, the required equation is aligned & (x-1)^2+(y+1)^2=7^2 & x^2+y^2-2 x+2 y-47=0 aligned

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