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MHT CET20226 Aug 2022Evening ShiftMathematicsCircleActual

If the line 3 x-4 y-7=0 and 2 x-3 y-5=0 pass through diameters of a circle of area 49 square units, then the equation of the circle is

Options

  1. Ax^2+y^2-2 x+2 y-47=0
  2. Bx^2+y^2+2 x-2 y-51=0
  3. Cx^2+y^2-2 x+2 y+51=0
  4. Dx^2+y^2+2 x+2 y+47=0

Correct answer

A. x^2+y^2-2 x+2 y-47=0

Step-by-step solution

Centre of the circle is the point of intersection of the diameters 3 x-4 y-7=0 and 2 x-3 y-5=0 which is (1,-1) and r=7 aligned & (x-1)^2+(y+1)^2=7^2 & x^2+y^2-2 x+2 y-47=0 aligned

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