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MHT CET20226 Aug 2022Morning ShiftMathematicsCircleActual

The equation of circle passing through the points (1,-2) and (4,-3) and whose centre lies on the line 3 x+2 y=7 is

Options

  1. Ax^2+y^2+6 x-2 y-5=0
  2. Bx^2+y^2-6 x-2 y+5=0
  3. Cx^2+y^2+6 x+2 y-5=0
  4. Dx^2+y^2-6 x+2 y+5=0

Correct answer

D. x^2+y^2-6 x+2 y+5=0

Step-by-step solution

Let the equation of the required circle be x^2+y^2+2 g x+2 f y-C=0 from (iii) + (iv) 9 g=-27 g=-3 then f=1 and c=5 So, the required equation is x^2+y^2-6 x+2 y+5=0

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