MHT CET202123 Sep 2021Morning ShiftMathematicsCircleActual

Equation of the chord of the circle x^2+y^2-4 x-10 y+25=0 having mid-point (1,2) is

Options

A-x+3 y=5
Bx+3 y=7
C5 x+y=7
D3 x+y=5

Correct answer

B. x+3 y=7

Step-by-step solution

aligned & x^2+y^2-4 x-10 y+25=0 centre =(2,5) and & radius = 4+25-25 =2 aligned Refer figure Let M (1,2) be the midpoint of chord Slope of CM = 2-5 1-2 =3 Slope of AB = -1 3 Equation of AB is ( y -2)= -1 3 ( x -1) i.e. x +3 y =7

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