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MHT CET202121 Sep 2021Evening ShiftMathematicsCircleActual

The equation of circle with centre at (2,-3) and the circumference 10 units is

Options

  1. Ax^2+y^2-4 x+6 y-12=0
  2. Bx^2+y^2-4 x-6 y-12=0
  3. Cx^2+y^2+4 x+6 y+12=0
  4. Dx^2+y^2-4 x+6 y+12=0

Correct answer

A. x^2+y^2-4 x+6 y-12=0

Step-by-step solution

We have 2 r=10 r=5 and centre of circle is (2,-3) Hence equation of circle is (x-2)^2+(y+3)^2=(5)^2 i.e. x^2+y^2-4 x+6 y-12=0

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