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MHT CET202020 Oct 2020Morning ShiftMathematicsCircleActual

The equation of the circle, the end-points of whose diameter are the centres of the circles x²+y²-2 x+3 y-3=0 and x²+y²+6 x-12 y-5=0 is

Options

  1. A2 x²+2 y²+4 x-9 y-24=0
  2. B2 x²+2 y²+4 x+9 y-24=0
  3. C2 x²+2 y²+4 x-9 y+24=0
  4. D2 x²+2 y²-4 x-9 y-24=0

Correct answer

A. 2 x²+2 y²+4 x-9 y-24=0

Step-by-step solution

Since the quadrilateral A B C D is cyclic, we have A + C =180^ and B + D =180^ A = (180^ - C ) =- C B = (180^ - D ) =- D A + B + C + D =0

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