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MHT CET202013 Oct 2020Evening ShiftMathematicsCircleActual

The equation of the circle whose end points of a diameter are the centres of the circles x²+y²+2 x-4 y+1=0 and x²+y²-8 x+6 y+17=0 is

Options

  1. Ax²+y²-3 x-y-10=0
  2. Bx²+y²+3 x-y-10=0
  3. Cx²+y²+3 x+y-10=0
  4. Dx²+y²-3 x+y-10=0

Correct answer

D. x²+y²-3 x+y-10=0

Step-by-step solution

Let centres of given circles be A(-1,2) and B(4,-3) By diameter form of equation of circle, we write array l (x+1)(x-4)+(y-2)(y+3)=0 x²-4 x+x-4+y²+3 y-2 y-6 x²+y²-3 x+y-10=0 array =0

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