If the circles x²+y²+2 x+2 k y+6=0 , x²+y²+2 k y+k=0 intersect orthogonally, then k is

Step-by-step solution

Since, circles cut orthogonally, if aligned & & 2 g g^ +2 f f^ =c+c^ & & 0+2 k²=6+k & & 2 k²-k-6=0 & &(2 k+3)(k-2)=0 aligned k=2 or -3 / 2