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MHT CET2011MathematicsCircle

The equation of a circle which has a tangent 3 x+4 y=6 and two normals given by (x-1)(y-2)=0 is

Options

  1. A(x-3)²+(y-4)²=5²
  2. Bx²+y²-4 x-2 y+4=0
  3. Cx²+y²-2 x-4 y+4=0
  4. Dx²+y²-2 x-4 y+5=0

Correct answer

C. x²+y²-2 x-4 y+4=0

Step-by-step solution

(x-1)(y-2)=0 array ll x-1=0 and y-2=0 Radius = 3(1)+4(2)-6 9+16 = 5 5 =1 array Equation of the circle is (x-1)²+(y-2)²=1 or x²+y²-2 x-4 y+4=0

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