MHT CET2007MathematicsCircle

If the points (2,0),(0,1),(4,5) and (0, c) are concyclic, then the value of c is

Options

A1
B14 3
C5
DNone of these

Correct answer

B. 14 3

Step-by-step solution

The equation of the circle passing through (2,0),(0,1) and (4,5) is 3 (x²+y² )-13 x-17 y+14=0 This passes through (0, c) . array l 3 c²-17 c+14=0 c=1, 14 3 array Since, c=1 is already there, for point (0,1) . Therefore, we take c= 14 3 .

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