Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202613 April 2026Morning ShiftMathematicsComplex NumberActual

The polar form of the complex number z = 1 1 + i , (where i = -1 ) is

Options

  1. A1 2 ( 7 4 + i 7 4 )
  2. B1 2 ( 4 + i 4 )
  3. C1 2 ( 4 + i 4 )
  4. D1 2 ( 7 4 + i 7 4 )

Correct answer

A. 1 2 ( 7 4 + i 7 4 )

Step-by-step solution

z = 1 1 + i Multiplying the numerator and denominator by the conjugate of the denominator: z = 1(1 - i) (1 + i)(1 - i) = 1 - i 1^2 - i^2 = 1 - i 2 = 1 2 - 1 2 i The modulus of z is: r = |z| = ( 1 2 )^2 + (- 1 2 )^2 = 1 4 + 1 4 = 1 2 = 1 2 The argument of z is: = ⁻¹ ( -1/2 1/2 ) = ⁻¹(-1) Since z lies in the fourth quadrant, = 2 - 4 = 7 4 . Thus, the polar form of z is: z = r( + i ) = 1 2 ( 7 4 + i 7 4 ) Answer: 1 2 ( 7 4 + i 7 4 )

Practice Complex Number on Quantrex Academy →

More from Complex Number

If z and are two non-zero complex numbers such that |z |=1 and Arg z- Arg = 2 then z = 2025Let z satisfy |z|=1, z=1- z and Im (z)>0 Statement-I : z is a real number Statement-II : Principal argument of z is 3 . Then 2025If ₁ and ₂ are two non-zero complex numbers and a , b are non zero real numbers such that | a ₁+ b ₂ |= | a ₁- b ₂ | , then ₁ ₂ is 2025If a complex number z=x+i y represents a point P on the Argand plane and Arg ( z-3+2 i z+2-3 i )= 4 , then the locus of P is a 2025By taking a i b =x i y, x>0 , if we get 21+12 2 i 21-12 2 i =a+i b , then b a = 2025Two values of (-8-8 3 i)^ 1 / 4 are 2025If x=3-2 3 i , then x^4-12 x^3+54 x^2-108 x-54= 2025z ₁, z ₂, z ₃ represent the vertices A , B , C of a triangle ABC respectively in the Argand plane. If |z₁-z₂ |= 25-12 3 , | z₁-z₃ z₂-z₃ |= 3 4 and ACB =30^ , then the area (in sq. 2025 Full Complex Number list All MHT CET PYQs