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MHT CET202618 April 2026Morning ShiftMathematicsContinuity and DifferentiabilityActual

The number of point / points where the function f(x) = 1 x^2-5|x|+6 is discontinuous is......

Options

  1. A0
  2. B1
  3. C2
  4. D4

Correct answer

D. 4

Step-by-step solution

The function f(x) = 1 x^2-5|x|+6 is discontinuous at the points where its denominator is zero. x^2 - 5|x| + 6 = 0 Since x^2 = |x|^2 , the equation can be written as: |x|^2 - 5|x| + 6 = 0 (|x| - 2)(|x| - 3) = 0 |x| = 2 x = 2 |x| = 3 x = 3 The points of discontinuity are x = -3, -2, 2, 3 . The number of points where the function is discontinuous is 4 . Answer: 4

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