MHT CET202523 Apr 2025Evening ShiftMathematicsContinuity and DifferentiabilityActual
The function f (x)=2 x- |x-x^2 | is
Options
- Acontinuous at x=1 .
- Bdiscontinuous at x=1 .
- Cnot defined at x=1 .
- Ddiscontinuous at x=0 .
Correct answer
A. continuous at x=1 .
Step-by-step solution
The continuity of f(x)=2x-|x-x^2| depends on the absolute value term, which requires piecewise definition. Analyzing x - x^2 = x(1 - x) , we observe that |x - x^2| = x - x^2 for 0 x 1 where x(1 - x) 0 , and |x - x^2| = x^2 - x otherwise. This gives the piecewise form: f(x) = cases 3x - x^2 & if x 1 cases To verify continuity at x = 1 , compute f(1) = 1^2 + 1 = 2 , the left-hand limit _ x 1^- (x^2 + x) = 2 , and the right-hand limit _ x 1^+ (3x - x^2) = 2 . The equality of these values confirms continuity at x = 1 .