If the function f(x) is continuous on its domain [-2,2] where f(x)= a x x +3,-2 x < 0=x+5,0 x 1= x^2+8 -b, 1 < x 2 , then 7 a+b+1 is equal to

Step-by-step solution

for continuity at x=0, _ x 0 - a x x +3=5 aligned & a+3=5 & a=2 aligned for continuity at x=1 , aligned & 6= _ x 1 + x^2+8 -b & 6= 1^2+8 -b & b=-3 aligned Now 7 a+b+1=7 2-3+1=12