MHT CET20225 Aug 2022Evening ShiftMathematicsContinuity and DifferentiabilityActual
If f ( x )=K+1 , for x=0 is continuous at x=0 , then value of K is
Options
- A1
- Be ⁻¹
- C0
- De
Correct answer
C. 0
Step-by-step solution
For continuity at x =0 aligned & _ x 0 f(x)=f(0) _ x 0 ( ^2 x ) ^2 x=K+1 & _ x 0 (1+ ^2 x )^ 1 ^2 x =K+1 & _e=K+1 & 1=K+1 & K=0 aligned