MHT CET202019 Oct 2020Morning ShiftMathematicsContinuity and DifferentiabilityActual
If aligned f(x) &= 4 x 5 x for x 0 &=2 k for x=0 aligned is continuous at x=0 , then the value of k is
Options
- A2 5
- B5
- C10
- D4 5
Correct answer
A. 2 5
Step-by-step solution
(C) Since f(x) is continuous at x=0 , array l _ x 0 f(x)=f(0) _ x 0 4 x 5 x =2 k _ x 0 ( 4 x x ) 5 =2 k (1) 4 5 =2 k k= 2 5 array