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MHT CET202016 Oct 2020Morning ShiftMathematicsContinuity and DifferentiabilityActual

The points of discontinuity of the function f(x)= 1 x-1 if 0 x 2= x+5 x+3 if 2 < x 4 in its domain are

Options

  1. Ax=2 only
  2. Bx=1, x=2
  3. Cx=4 only
  4. Dx=0, x=2

Correct answer

B. x=1, x=2

Step-by-step solution

(B) aligned f(x) &= 1 x-1 , if 0 x 2 f(x) is not defined at x=1 &= x+5 x+3 , if 2 < x 4 aligned _ x 2⁻ f(x)= 1 2-1 =1 and _ x 2⁺ f(x)= 7 5 Thus f(x) is not continuous at x=2

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