Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202620 April 2026Morning ShiftMathematicsDefinite IntegrationActual

If ₀^1 dx x + 1 - x = 2 k , then the value of k is...

Options

  1. A4 3
  2. B4 3
  3. C2 3
  4. D2 3

Correct answer

B. 4 3

Step-by-step solution

Rationalizing the denominator of the integrand: ₀^1 dx x + 1 - x = ₀^1 x + 1 + x ( x + 1 )^2 - ( x )^2 dx = ₀^1 ( x + 1 + x ) dx Integrating with respect to x : = [ 2 3 (x + 1)^ 3/2 + 2 3 x^ 3/2 ]₀^1 Applying the limits: = ( 2 3 (2)^ 3/2 + 2 3 (1)^ 3/2 ) - ( 2 3 (1)^ 3/2 + 0 ) = 4 2 3 + 2 3 - 2 3 = 4 2 3 Equating to the given value 2 k : 2 k = 4 2 3 k = 4 3 Answer: 4 3

Practice Definite Integration on Quantrex Academy →

More from Definite Integration

₀^1 2 x+5 x^2+3 x+2 ~d x= 2025₀^1 x^ 5 / 2 (1-x)^ 3 / 2 ~d x= 2025_ n [ 1 n^2 ^2 1 n^2 + 2 n^2 ^2 4 n^2 + 3 n^2 ^2 9 n^2 + + 1 n^2 ^2 1 ]= 2025₀^1 x Sin ⁻¹ x d x= 2025_ - 2 ^ 2 (x-[x]) d x= 2025₀^2 x^2(2-x)^5 d x= 2025If f(x)= Max x^3-4, x^4-4 , and g(x)= Min x^2, x^3 , then _ -1 ^1(f(x)-g(x)) d x= 2025_ n 2 n [ 2 n + 2 2 n + 3 2 n + + 2 ]= 2025 Full Definite Integration list All MHT CET PYQs