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MHT CET202617 April 2026Evening ShiftMathematicsDefinite IntegrationActual

The function f(x) = ₀^x dt 1 + t satisfies which of the following differential equations?

Options

  1. A2 df dx = 1 + [f(x)]^2
  2. Bdf dx = 1 + [f(x)]^2
  3. C2 df dx = 1 - [f(x)]^2
  4. Ddf dx = 1 - [f(x)]^2

Correct answer

A. 2 df dx = 1 + [f(x)]^2

Step-by-step solution

Given f(x) = ₀^x dt 1 + t Using the half-angle formula 1 + t = 2 ^2(t/2) , we get: f(x) = ₀^x dt 2 ^2(t/2) = 1 2 ₀^x ^2(t/2) dt Integrating, we obtain: f(x) = [ (t/2) ]₀^x = (x/2) Differentiating f(x) with respect to x : df dx = 1 2 ^2(x/2) Using the identity ^2(x/2) = 1 + ^2(x/2) : df dx = 1 2 ( 1 + ^2(x/2) ) Substituting f(x) = (x/2) : df dx = 1 2 ( 1 + [f(x)]^2 ) 2 df dx = 1 + [f(x)]^2

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