Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202617 April 2026Morning ShiftMathematicsDefinite IntegrationActual

The value of ₀^ 1 1 + 2^ x ,dx is _____

Options

  1. A2
  2. B2
  3. C3 2

Correct answer

A. 2

Step-by-step solution

Let I = ₀^ 1 1 + 2^ x , dx Using the property ₀^a f(x) , dx = ₀^a f(a-x) , dx , we get: I = ₀^ 1 1 + 2^ ( - x) , dx I = ₀^ 1 1 + 2^ - x , dx I = ₀^ 2^ x 2^ x + 1 , dx Adding the two equations for I : 2I = ₀^ ( 1 1 + 2^ x + 2^ x 1 + 2^ x ) , dx 2I = ₀^ 1 , dx 2I = I = 2 Answer: 2

Practice Definite Integration on Quantrex Academy →

More from Definite Integration

₀^1 2 x+5 x^2+3 x+2 ~d x= 2025₀^1 x^ 5 / 2 (1-x)^ 3 / 2 ~d x= 2025_ n [ 1 n^2 ^2 1 n^2 + 2 n^2 ^2 4 n^2 + 3 n^2 ^2 9 n^2 + + 1 n^2 ^2 1 ]= 2025₀^1 x Sin ⁻¹ x d x= 2025_ - 2 ^ 2 (x-[x]) d x= 2025₀^2 x^2(2-x)^5 d x= 2025If f(x)= Max x^3-4, x^4-4 , and g(x)= Min x^2, x^3 , then _ -1 ^1(f(x)-g(x)) d x= 2025_ n 2 n [ 2 n + 2 2 n + 3 2 n + + 2 ]= 2025 Full Definite Integration list All MHT CET PYQs