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MHT CET20226 Aug 2022Evening ShiftMathematicsDefinite IntegrationActual

₀^2[x] d x+ ₀^2|x-1| d x= (where [x] denotes the greatest integer function.)

Options

  1. A3
  2. B4
  3. C1
  4. D2

Correct answer

D. 2

Step-by-step solution

aligned & ₀^2[x] d x+ ₀^2[x-1] d x & = ₀^1 0 . d x+ ₁^2 1 . d x+ ₀^1(1-x) d x+ ₁^2(x-1) d x & =[0]₀^1+[x]₁^2+ [x- x^2 2 ]₀^1+ [ x^2 2 -x ]₁^2 & =0+1+ 1 2 + 1 2 =2 aligned

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