Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202121 Sep 2021Morning ShiftMathematicsDefinite IntegrationActual

If f ( x )=| x -1|+| x -2|+| x -3|, x [1,4] , then ₁^4 f ( x ) dx =

Options

  1. A1 2
  2. B7
  3. C9 2
  4. D19 2

Correct answer

D. 19 2

Step-by-step solution

aligned & ₁^4 f(x) d x= ₁^4[|x-1|+|x-2|+|x-3| d x & = ₁^2(x-1)+(2-x)+(3-x) d x+ ₂^3[(x-1)+(x-2)+(3-x)] d x & + ₃^4[(x-1)+(x-2)+(x-3)] d x & = ₁^2(4-x) d x+ ₂^3 x d x+ ₃^4(3 x-6) d x aligned aligned & = [4 x- x^2 2 ]₁^2+ [ x^2 2 ]₂^3+ [ 3 x^2 2 -6 x ]₃^4 & = [(8-2)- (4- 1 2 ) ]+ [ ( 9 2 -2 ) ]+ [(24-24)- ( 27 2 -18 ) ] & = (2+ 1 2 )+ ( 5 2 )+ ( 9 2 )= 19 2 aligned

Practice Definite Integration on Quantrex Academy →

More from Definite Integration

₀^1 2 x+5 x^2+3 x+2 ~d x= 2025₀^1 x^ 5 / 2 (1-x)^ 3 / 2 ~d x= 2025_ n [ 1 n^2 ^2 1 n^2 + 2 n^2 ^2 4 n^2 + 3 n^2 ^2 9 n^2 + + 1 n^2 ^2 1 ]= 2025₀^1 x Sin ⁻¹ x d x= 2025_ - 2 ^ 2 (x-[x]) d x= 2025₀^2 x^2(2-x)^5 d x= 2025If f(x)= Max x^3-4, x^4-4 , and g(x)= Min x^2, x^3 , then _ -1 ^1(f(x)-g(x)) d x= 2025_ n 2 n [ 2 n + 2 2 n + 3 2 n + + 2 ]= 2025 Full Definite Integration list All MHT CET PYQs