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MHT CET202020 Oct 2020Morning ShiftMathematicsDefinite IntegrationActual

₀^ e^ x (e^ x +e^ - x) . d x=

Options

  1. A- 2
  2. B-
  3. C2

Correct answer

3

Step-by-step solution

Let aligned I &= ₀^ e^ x e^ x +e^ - x d x ...(1) &= ₀^ e^ ( -x) e^ ( -x) +e^ - ( -x) d x &= ₀^ e^ - x e^ - x +e^ x d x ...(2) aligned Adding equation (1) & (2), we get 2 I= ₀^ 1 d x=[x]₀^ I= 2

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