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AP EAMCET202316 May 2023Evening ShiftMathematicsApplication of DerivativesActual

If the slope of the tangent on a curve at any point (x, y) is equal to y^2-x^2 2 x y , then the equation of the normal at the point ( 1 2 , 3 2 ) is

Options

  1. A3 x + y = 3
  2. Bx+ 3 y= 3
  3. C3 x- 3 y=0
  4. Dx+ 3 y=0

Correct answer

A. 3 x + y = 3

Step-by-step solution

Given, d y d x = y^2-x^2 2 x y at, ( 1 2 , 3 2 ) ; dy dx = 3 4 - 1 4 2 1 2 3 2 = 2 4 2 3 4 = 1 3 Now, equation of normal is aligned & y- 3 2 =- 3 (x- 1 2 ) & 2 3 x+2 y=2 3 3 x+y= 3 aligned

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