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MHT CET202013 Oct 2020Evening ShiftMathematicsDefinite IntegrationActual

₀^ 2 [3] x [3] x + [3] cosec x d x=

Options

  1. A0
  2. B4
  3. C2
  4. D- 4

Correct answer

B. 4

Step-by-step solution

Let aligned I &= ₀^ 2 [3] x [3] x + [3] cosec x dx ...(1) &= ₀^ 2 [3] ( 2 -x ) ( 2 -x )+ [3] cosec ( 2 -x ) [3] 2 d x I =& ₀^ 2 [3] x + [3] cosec x d x ...(2) aligned Adding equation (1) & (2), we get 2 I= ₀^ 2 1 d x=[x]₀^ 2 2 I= 2 -0 I= 4

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