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MHT CET202012 Oct 2020Morning ShiftMathematicsDefinite IntegrationActual

₀^ 2 x x 1+ ⁴ x d x=

Options

  1. A6
  2. B8
  3. C2
  4. D4

Correct answer

B. 8

Step-by-step solution

I= ₀^ 2 x x 1+ ⁴ x d x = 1 2 ₀^ 2 2 x x 1+ ( ² x )² d x Put ² x=t 2 x x d x=d t When x=0, t=0 and when x= 2 , t=1 I= 1 2 ₀¹ dt 1+ t ² = 1 2 [ ⁻¹ t ]₀¹= 1 2 [ 4 -0 ]= 8

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