MHT CET2019Evening ShiftMathematicsDefinite IntegrationActual
∫ 0 1 x 1 - x 5 d x = … … .
Options
- A1 5
- B1 42
- C1 13
- D13 42
Correct answer
B. 1 42
Step-by-step solution
Let = l = ∫ 0 1 x 1 - x 5 d x Put 1 - x = t ⇒ x = 1 - t ⇒ - d x = d t ⇒ d x = - d t When x = 0 ' , then t = 1 and When x = 1 , t h e n t = 0 ∴ l ∫ 1 0 1 - t t 5 - d t = ∫ 0 1 t 5 - t 6 d t = t 6 6 - t 7 7 = 1 6 1 6 - 1 7 1 7 = 7 - 6 42 = 1 42