MHT CET2017MathematicsDefinite Integration
∫ 0 1 x tan - 1 x d x =
Options
- Aπ 4 + 1 2
- Bπ 4 - 1 2
- C1 2 - π 4
- D- π 4 - 1 2
Correct answer
B. π 4 - 1 2
Step-by-step solution
∫ 0 ( u v r u l e ) 1 x tan - 1 x d x = tan - 1 x ∫ x d x 0 1 - ∫ 0 1 d d x tan - 1 x ∫ x d x d x = tan - 1 x ⋅ x 2 2 0 1 - ∫ 0 1 1 1 + x 2 ⋅ x 2 2 d x = π 4 ⋅ 1 2 - 0 - 1 2 ∫ 0 1 x 2 1 + x 2 d x = π 8 - 1 2 ∫ 0 1 1 - 1 1 + x 2 d x = π 8 - 1 2 x - tan - 1 x 0 1 = π 8 - 1 2 1 - 0 - π 4 - 0 = π 8 - 1 2 + π 8 = π 4 - 1 2