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MHT CET2016MathematicsDefinite Integration

∫ - π 2 π 2 log ⁡ 2 - sin ⁡ x 2 + sin ⁡ x d x =

Options

  1. A1
  2. B3
  3. C2
  4. D0

Correct answer

D. 0

Step-by-step solution

Let I = ∫ - π 2 π 2 log ⁡ 2 - sin ⁡ x 2 + sin ⁡ x d x As given function f ( x ) = log ( 2 − sin x 2 + sin x ) is odd. ⇒ I = ∫ f ( x ) d x = 0

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