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MHT CET2011MathematicsDefinite Integration

By Simpson rule taking n=4 , the value of the integral ₀¹ 1 1+x² d x is equal to

Options

  1. A0.788
  2. B0.781
  3. C0.785
  4. DNone of these

Correct answer

C. 0.785

Step-by-step solution

Here, h=1 / 4,=0.25, y= 1 1+x² array c|c|c & x & y 1 & 0 & 1.0 2 & 0.25 & 0.941 3 & 0.5 & 0.8 4 & 0.75 & 0.64 5 & 1 & 0.5 array array c|c|c & x & y 1 & 0 & 1.0 2 & 0.25 & 0.941 3 & 0.5 & 0.8 4 & 0.75 & 0.64 5 & 1 & 0.5 array By Simpson's Rule array l ₀¹ d x 1+x² = 1 4 3 [(1+0.5)+4(0.941+0.64)+2(0.8)] = 1 12 [9.424]=0.785 array

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