MHT CET202522 Apr 2025Evening ShiftMathematicsDifferential EquationsActual
The equation of the curve passing through (2, 9 2 ) and having the slope (1- 1 x^2 ) at ( x , y ) is
Options
- Ax y=x^2+2 x+1
- Bx y=x^2+x+2
- Cx y=x^2+x+5
- Dx y=x^2+2 x+5
Correct answer
A. x y=x^2+2 x+1
Step-by-step solution
The slope at any point (x, y) is dy dx = 1 - 1 x^2 . Integrating both sides with respect to x yields y = (1 - x⁻²)dx = x + x⁻¹ + C . Given that the curve passes through (2, 9 2 ) , substitute to find C : 9 2 = 2 + 1 2 + C C = 2 The equation becomes y = x + 1 x + 2 . Multiplying through by x gives xy = x^2 + 1 + 2x = x^2 + 2x + 1 , which corresponds to option A .