MHT CET20249 May 2024Morning ShiftMathematicsDifferential EquationsActual
The curve satisfying the differential equation y ~d x- (x+3 y^2 ) dy =0 and passing through the point (1,1) also passes through the point
Options
- A( 1 4 , 1 2 )
- B( 1 4 ,- 1 2 )
- C( 1 3 ,- 1 3 )
- D(- 1 3 , 1 3 )
Correct answer
D. (- 1 3 , 1 3 )
Step-by-step solution
aligned & y ~d x- (x+3 y^2 ) d y=0 & y ~d x= (x+3 y^2 ) d y & ~d x ~d y = x+3 y^2 y & ~d x ~d y = x y +3 y & ~d x ~d y - ( 1 y ) x=3 y aligned Which is a linear equation IF = e ^ -1 y ~d y = e ^ - y = 1 y The required solution is x 1 y = 3 y 1 y ~d y+ c aligned & x y =3 y+c & x=3 y^2+c y aligned Curve passes through (1,1) aligned & 1=3+c & c=-2 aligned Equation (i) becomes, x=3 y^2-2 y Option (D) i.e., ( -1 3 , 1 3 ) Satisfies above equation.