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MHT CET20227 Aug 2022Evening ShiftMathematicsDifferential EquationsActual

The particular solution of d y d x =1+x+y^2+x y^2 , when y(0)=0 . is

Options

  1. Ay= (1+ x^2 2 )
  2. By^3= (1+ x^2 2 )
  3. Cy^2= (1+ x^2 2 )
  4. Dy= (x+ x^2 2 )

Correct answer

D. y= (x+ x^2 2 )

Step-by-step solution

aligned & d y d x =1+x+y^2+x y^2=(1+x) (1+y^2 ) & d y 1+y^2 = (1+x) d x & ⁻¹ y=x+ x^2 2 +c & y(0)=0 c=0 & ⁻¹ y=x+ x^2 2 & y= (x+ x^2 2 ) aligned

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