MHT CET20227 Aug 2022Morning ShiftMathematicsDifferential EquationsActual
The particular solution of the differential equation d y d x -e^x=y e^x , when x=0 and y=1 is
Options
- A( y+1 2 )= e^x 2 - 1 2
- B( y+1 2 )=e^x-1
- C(y-1)=e^x-1
- D2(y-1)=e^x-1
Correct answer
B. ( y+1 2 )=e^x-1
Step-by-step solution
aligned & d y d x -e^x=y e^x d y d x =(y+1) e^x d y y+1 = e^x d x & (y+1)=e^x+c & for x=0, y=1 c= 2-1 & Hence, (y+1)=e^x+ 2-1 & (y+1)- 2=e^x-1 & ( y+1 2 )=e^x-1 aligned