MHT CET202124 Sep 2021Morning ShiftMathematicsDifferential EquationsActual
The particular solution of the differential equation y(1+ x) d x d y -x x=0 when x=e, y=e^2 is
Options
- Ay^2=e^4 x
- By=e^2 x
- Cy=x^2 x
- Dy=e x x
Correct answer
D. y=e x x
Step-by-step solution
aligned & y(1+ x) d y d x -x x=0 & y(1+ x) d y d x =x x d y d x = y(1+ x) x x & d y d x = 1+ x x x d x & |y|+ |x x|+ c & We have x=e, y=e^2 & |e|^2= |e e|+ c & 2=1+ c c=1= e & |y|= |x x|+ e & y=e x x aligned