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MHT CET202122 Sep 2021Evening ShiftMathematicsDifferential EquationsActual

The particular solution of the differential equation d y d x = y+1 x^2-x , when x =2 and y =1 is

Options

  1. Ax y=4 x-6
  2. Bxy =2 x-2
  3. Cx y=x-2
  4. Dx y=-x+4

Correct answer

C. x y=x-2

Step-by-step solution

aligned & d y d x = y+1 x^2-x & d y y+1 = d x x(x-1) & d y y+1 = [ 1 x-1 - 1 x ] d x |y+1|= |x-1|- |x|+ & c & We have x=2 and y=1 & |2|= |1|- |1|+ c c=2 & |y+1|= |x-1|- |x|+ |2| & |y+1|= | 2(x-1) x | & y+1= 2(x-1) x x y+x=2 x-2 x y=x-2 aligned

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