MHT CET202015 Oct 2020Morning ShiftMathematicsDifferential EquationsActual
The differential equation whose solution is y=c₁ cosax +c₂ sinax ( . Where c₁ and c₂ are arbitrary constants) is
Options
- Ad² y d x² -a² y=0
- Bd² y d x² +a² y=0
- Cd² y d x² +a y²=0
- Dd² y d x² +y²=0
Correct answer
B. d² y d x² +a² y=0
Step-by-step solution
Given y=c₁ a x+c₂ a x d y d x =-a c₁ a x+a c₂ a x aligned y ( 1 1-x² ) &= x (1-x² )^ 1 2 1 (1-x² ) d x &= -1 2 -2 x (1-x² )^ 3 / 2 d x= (- 1 2 ) (1-x² )^ 1 2 (- 1 2 ) +c y ( 1 1-x² ) &= 1 1-x² +c y= 1-x² +c (1-x² ) aligned