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MHT CET202015 Oct 2020Morning ShiftMathematicsDifferential EquationsActual

The differential equation whose solution is y=c₁ cosax +c₂ sinax ( . Where c₁ and c₂ are arbitrary constants) is

Options

  1. Ad² y d x² -a² y=0
  2. Bd² y d x² +a² y=0
  3. Cd² y d x² +a y²=0
  4. Dd² y d x² +y²=0

Correct answer

B. d² y d x² +a² y=0

Step-by-step solution

Given y=c₁ a x+c₂ a x d y d x =-a c₁ a x+a c₂ a x aligned y ( 1 1-x² ) &= x (1-x² )^ 1 2 1 (1-x² ) d x &= -1 2 -2 x (1-x² )^ 3 / 2 d x= (- 1 2 ) (1-x² )^ 1 2 (- 1 2 ) +c y ( 1 1-x² ) &= 1 1-x² +c y= 1-x² +c (1-x² ) aligned

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