MHT CET202014 Oct 2020Evening ShiftMathematicsDifferential EquationsActual
The particular solution of the differential equation (y+x d y d x ) x y= x at x=0 is
Options
- Ax+ x y=1
- Bx- x y=1
- Cx- x y=1
- Dx+ x y=1
Correct answer
A. x+ x y=1
Step-by-step solution
We have (y+x d y d x ) x y= x Put x y=u x d y d x +y= d u d x ( du dx ) u = x u d u= x d x - u= x+c - x y= x+c When x=0 , we get - 0=0+c c=-1 - x y= x-1 x+ x y=1