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AP EAMCET20226 Jul 2022Morning ShiftMathematicsApplication of DerivativesActual

V is the set of points on the curve y^3-3 x y+2=0 where the tangent is vertical then V =

Options

  1. A(1,0)
  2. B(1,1)
  3. C(0.0)(1.1)

Correct answer

C. (0.0)(1.1)

Step-by-step solution

We have a curve y^3-3 x y+2=0 now differently the given curve w.r.t. x we get aligned & 3 y^2 y^1-3(y+x y)=0 & y^2 y^1-y-x y^1=0 & y^1 (y^2-x )=y & or y^1= y y^2-x aligned tangent is verticle y 2-x=0 and y 0 1 will satisfyn the obtained condition V = (1,1)

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