MHT CET202012 Oct 2020Evening ShiftMathematicsDifferential EquationsActual
The differential equation obtained by eliminating the arbitrary constants from the equation y²=(2 x+c)⁵ is
Options
- A( d y d x )⁴-625 y⁴=0
- B( d y d x )⁵-3125 y³=0
- C( d y d x )³-125 y³=0
- Dx y d y d x =5
Correct answer
B. ( d y d x )⁵-3125 y³=0
Step-by-step solution
We have y²=(2 x+c)⁵ ...(i) 2 y dy dx =5(2 x + c )⁴(2) y dy dx =5(2 x + c )⁴ (2 x+c)= [ y 5 ( d y d x ) ]^ 1 4 and substituting value of (2 x+c) in eq. (i), we write y²= [ y 5 ( d y d x ) ]^ 5 4 Raising both sides to power of 4 , we get aligned & y⁸= [ y 5 ( d y d x ) ]⁵= y⁵ 3125 ( d y d x )⁵ & 3125 y³= ( d y d x )⁵ aligned