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MHT CET20192 May 2019Morning ShiftMathematicsDifferential EquationsActual

The general solution of the differential equation of all circles having centre at A - 1 , 2 is ________

Options

  1. Ax 2 + y 2 + x - 2 y + c = 0
  2. Bx 2 + y 2 - 2 x + 4 y + c = 0
  3. Cx 2 + y 2 - x + 2 y + c = 0
  4. Dx 2 + y 2 + 2 x - 4 y + c = 0

Correct answer

D. x 2 + y 2 + 2 x - 4 y + c = 0

Step-by-step solution

Equation of circle is x 2 + y 2 + 2 x - 4 y + c = 0 Whose centre is - 1 , 2

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