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MHT CET2019Morning ShiftMathematicsDifferential EquationsActual

The solution of differential equation x 2 + 1 d y d x + y 2 + 1 = 0 is….

Options

  1. Ax + y = c
  2. Bx 2 + 1 y 2 + 1 = c
  3. Cx 2 = y 2 + c
  4. Dt a n - 1 x + t a n - 1 y = c

Correct answer

D. t a n - 1 x + t a n - 1 y = c

Step-by-step solution

We have, differential equation x 2 + 1 d y d x + y 2 + 1 = 0 ⇒ d x x 2 + 1 = - d y y 2 + 1 On the integrating both sides, we get ∫ d x x 2 + 1 = - d y y 2 + 1 ⇒ t a n - 1 x = - t a n - 1 y + C ⇒ t a n - 1 x + t a n - 1 y = C

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