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MHT CET2011MathematicsDifferential Equations

The differential equation of all circles which pass through the origin and whose centres lie on y -axis is

Options

  1. A(x²-y² ) d y d x -2 x y=0
  2. B(x²-y² ) d y d x +2 x y=0
  3. C(x²-y² ) d y d x -x y=0
  4. D(x²-y² ) d y d x +x y=0

Correct answer

A. (x²-y² ) d y d x -2 x y=0

Step-by-step solution

Equation of a circle is array r x²+(y-a)²=a² 2 x+2 y d y d x -2 a d y d x =0 array Form Eqs. (i) and (ii) aligned d y d x &= 2 x y x²-y² (x²-y² ) d y d x -2 x y &=0 aligned

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