MHT CET202613 April 2026Evening ShiftMathematicsDifferentiationActual
d dx [ ^2 ⁻¹ 1-x 1+x ] = ...
Options
- A-1
- B1 2
- C-1 2
- D1
Correct answer
B. 1 2
Step-by-step solution
Let y = ^2 ⁻¹ 1-x 1+x Let ⁻¹ 1-x 1+x = = 1-x 1+x ^2 = 1-x 1+x We know that ^2 = 1 ^2 = 1 1 + ^2 Substituting the value of ^2 : ^2 = 1 1 + 1-x 1+x = 1+x 1+x+1-x = 1+x 2 Therefore, y = 1+x 2 Differentiating with respect to x : dy dx = d dx ( 1+x 2 ) = 1 2