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MHT CET202416 May 2024Evening ShiftMathematicsDifferentiationActual

If g (x)=[ f (2 f (x)+2)]^2 and f (0)=-1, f ^ (0)=1 , then g^ (0) is

Options

  1. A-4
  2. B4
  3. C-3
  4. D3

Correct answer

A. -4

Step-by-step solution

1. (A). Std. 12 Part-2 | Ch -1| Exercise-1.1 aligned g (x) & = f [2 f (x)+2] ^2 ~g ^ (x) & =2 f [2 f (x)+2] f ^ [2 f (x)+2] 2 f ^ (x) g ^ (0) & =2 f [2 f (0)+2] f ^ [2 f (0)+2] 2 f ^ (0) & =2 f [2(-1)+2] f ^ (2(-1)+2) 2(1) g ^ (0) & =4 f (0) f ^ (0) & =4(-1)(1) & =-4 aligned

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