If y= ⁻¹ ( x^2 1+( x)^2 ) , then ( d y ~d x )_ d x-1 =

Step-by-step solution

y= ⁻¹ ( x^2 1+( x)^2 )= ⁻¹ ( 2 x 1+( x)^2 ) Let x= array ll & y= ⁻¹ ( 2 1+ 2 )= ⁻¹( 2 )=2 & y=2 ⁻¹( x) & d y ~d x =2 1 1+( x)^2 1 x & . ( ~d y ~d x ) |_ at x=1 =2 array